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6x^2-7.96x=0
a = 6; b = -7.96; c = 0;
Δ = b2-4ac
Δ = -7.962-4·6·0
Δ = 63.3616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.96)-\sqrt{63.3616}}{2*6}=\frac{7.96-\sqrt{63.3616}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.96)+\sqrt{63.3616}}{2*6}=\frac{7.96+\sqrt{63.3616}}{12} $
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